If a square is inscribed in a circle, then the ratio of the areas of the circle and the square is
A
π:2
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B
2:π
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C
πr:2
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D
2:πr
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Solution
The correct option is Aπ:2 Let side of square = a radius of circle = r From △OEB △OEB is right angled triangle Applying pythagoroes theorem OE2+EB2=OB2 (a2)2+(a2)2=r2 2a24r a2=2r2 a=√2r2 AreaofcircleAreaofsquare=πr2a2=πr22r2=π:2