If a square is inscribed in a circle, then the ratio of the areas of the circle and the square is
A
π:2
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B
2:π
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C
πr:2
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D
2:πr
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Solution
The correct option is Aπ:2
Let side of square =a Radius of circle =r. From ΔOEB ΔOEB is right angled triangle Applying pythagoroes theorem OE2+EB2=OB2 (a2)2+(a2)2=r2 2a24=r2 a2=2r2 a=√2r. AreaofcircleAreaofsquare=πr2a2 =πr22r2 =π:2.