If a square of side 8m and a rectangle of length 12m have the same perimeter, then find the area of the rectangle(in m2)?
48 m2
Let the side of a square be 'a' and length and breadth of a rectangle be 'l' and 'b' respectively.
Given,
Perimeter of square = Perimeter of rectangle
4a = 2(l +b)
4 × 8 = 2(12 + b)
32 = 24 + 2b
8 = 2b
Hence b = 4 m
Area of rectangle = l × b = 12 × 4 = 48 m2