Question

If $A$ stands for $+$, $B$ stands for $-,$ $C$ stand for $\times$, then what is the value of $\left(10C4\right)+\left(4C4\right)B6?$

• A. $60$
• B. $56$
• C. $50$
• D. $20$

Answer 1

The correct option is C $50$

Given expression is $\left(10C4\right)+\left(4C4\right)B6$

Using given conditions, we reduce the above expression as

$(10\times 4)+(4\times 4)-6=50$

Hence, the answer is $50$.