If a star converts all of its Helium into Oxygen nucleus, find the amount of energy released per nucleus of Oxygen.
( $H e = 4.0026 a m u$
$O = 15.9994 a m u$ )

7.26 M e V

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7 M e V

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10.24 M e V

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5.12 M e V

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Solution

The correct option is C $10.24 M e V$
$E = △ m c^{2} △ m = 4 \times m_{H e} - m_{O} = 0.011 a m u \Rightarrow E = 0.011 \times 1.66 \times 10^{- 27} \times 9 \times 10^{16} J 1 e V = 1.6 \times 10^{- 19} J \Rightarrow E = 10.24 M e V$

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Similar questions

Q. If a star can convert all the He nuclei completely into oxygen nuclei, the energy released per oxygen nuclei is:

[Mass of

H e

nucleus is

4.0026 a m u

and mass of oxygen nucleus is

15.9994 a m u

]

If a star converts all the helium $(H e)$ nuclei completely into oxygen $(O)$ nuclei, the energy released per oxygen nucleus is (mass of helium nucleus = $4.0026 a m u$ and mass of oxygen nucleus = $15.9994 a m u$ )

Q. A star converts all its

H e

in Oxygen. Find the amount of energy released per nucleus of oxygen.

H e

4.0026

amu

O

15.9994

amu

Q. If a star can convert all of the Helium nuclei, completely into oxygen nuclei, the energy released per oxygen nucleus is,
[Mass of Helium nucleus

= 4.0026 amu

and mass of Oxygen nucleus

= 15.9994 amu

]

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If a star converts all of its Helium into Oxygen nucleus, find the amount of energy released per nucleus of Oxygen.(He=4.0026 amuO=15.9994 amu)

The correct option is C 10.24 MeVE=△mc2△m=4×mHe−mO=0.011 amu⇒E=0.011×1.66×10−27×9×1016 J1 eV=1.6×10−19 J⇒ E=10.24 MeV

If a star converts all of its Helium into Oxygen nucleus, find the amount of energy released per nucleus of Oxygen.
( $H e = 4.0026 a m u$
$O = 15.9994 a m u$ )

The correct option is C $10.24 M e V$
$E = △ m c^{2} △ m = 4 \times m_{H e} - m_{O} = 0.011 a m u \Rightarrow E = 0.011 \times 1.66 \times 10^{- 27} \times 9 \times 10^{16} J 1 e V = 1.6 \times 10^{- 19} J \Rightarrow E = 10.24 M e V$