If a steam-jacket eudiometer with 23ml of oxygen and 4ml of hydrogen are mixed over mercury, determine the total volume in ml of the gas after the mixture was sparked?

16

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25

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34

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36

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40

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Solution

The correct option is B $25$
$2 H_{2} + O_{2} \to 2 H_{2} O$
2 moles of hydrogen will react with 1 mole of oxygen to form 2 moles of water.
Volume is directly proportional to the number of moles.
4 ml of hydrogen will react with $\frac{4 \times 1}{2} = 2$ ml of oxygen to form 4 ml of water.
$23 - 2 = 21 m l$ of oxygen will be left uncombined.
Thus, after the mixture was sparked, 21 ml oxygen and 4 ml water are present.
Total volume of the gas after the mixture was sparked $= 21 + 4 = 25$ ml.

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