If a straight line passing through the origin O meets the lines 4x+2y=9 and 2x+y+6=0 at the points P and Q respectively, then the ratio in which O devides the segment PQ is
A
3:4
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B
4:3
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C
2:5
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D
5:2
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Solution
The correct option is A3:4 Given lines are 4x+2y−9=0 and 2x+y+6=0 Since the constant term in the equation of lines have opposite signs, origin lies in between two lines.
So, OPOQ=OMON⇒OPOQ=|9|√16+4|6|√4+1⇒OPOQ=34 ∴OP:OQ=3:4