If a straight line passing through the point P(−3,4) is such that its intercepted portion between the coordinate axes is bisected at P, the its equation is :
A
4x+3y=0
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B
x−y+7=0
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C
3x−4y+25=0
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D
4x−3y+24=0
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Solution
The correct option is D4x−3y+24=0 Let the line cuts x-axis and y-axis at A(h,0) and B(0,k) respectively. ∴ Coordinates of mid-point of AB is P P(−3,4)≡(h2,k2) ∴h=−6 and k=8
Therefore, equation of line is x−6+y8=1 ⇒4x−3y+24=0