If a straight line y = 2x +k passes through the point (1, 2), then the value of k is equal to
Substituting the value of x and y in the given equation of line, we get
⇒ 2 = 2×1 +k
⇒ k = 0
A line with positive direction cosine passes through the point P(2, – 1, 2) and makes equal angles with coordinate axes. The line meets the plane 2x + y + z = 9 at Q. Then the length of line segment PQ is equal to
The value of ‘k’ for which the points (1, 2), (5, 6) and (k, 1) are collinear is