If a stretched wire is vibrating in the second overtone, then the number of nodes and antinodes between the ends of the string are respectively
A
2 and 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 and 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 and 3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2 and 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
3 and 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 4 and 3 For third harmonic second overtone So, the number of nodes =4 N and the number of antinodes =3 A NOTE Ambiguous statement in question . Our solution considers the end nodes also.