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Question

If a stretched wire is vibrating in the second overtone, then the number of nodes and antinodes between the ends of the string are respectively

A
2 and 2
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B
1 and 2
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C
4 and 3
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D
2 and 3
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E
3 and 4
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Solution

The correct option is C 4 and 3
For third harmonic second overtone
So, the number of nodes =4 N
and the number of antinodes =3 A
NOTE Ambiguous statement in question . Our solution considers the end nodes also.
723642_671982_ans_0e8793592e3345a69e82d14aab0fec9e.PNG

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