If a strong diffraction peak is observed when electron are incident at an angle. 'i' from the normal to the crystal planes with distance 'd' wavelength them (see figure) de Broglie wavelength $λ_{d B}$ of electrons can be calculate by the relationship (n is an integer)

d s i n = n λ_{d B}

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2 d c o s i = n λ_{d B}

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d s i n = i λ_{d B}

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d c o s = i λ_{d B}

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Solution

The correct option is B $2 d c o s i = n λ_{d B}$

Bragg's relation $n λ = 2 d sin θ$ for having an in density maximum for diffraction pattern. But as the angle of incidence is given their $n λ = 2 d c o s i$ is the formula for finding a peat.

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If a strong diffraction peak is observed when electron are incident at an angle. 'i' from the normal to the crystal planes with distance 'd' wavelength them (see figure) de Broglie wavelength λdB of electrons can be calculate by the relationship (n is an integer)

The correct option is B 2dcosi=nλdBBragg's relation nλ=2dsinθ for having an in density maximum for diffraction pattern. But as the angle of incidence is given their nλ=2dcosi is the formula for finding a peat.

If a strong diffraction peak is observed when electron are incident at an angle. 'i' from the normal to the crystal planes with distance 'd' wavelength them (see figure) de Broglie wavelength $λ_{d B}$ of electrons can be calculate by the relationship (n is an integer)

The correct option is B $2 d c o s i = n λ_{d B}$

Bragg's relation $n λ = 2 d sin θ$ for having an in density maximum for diffraction pattern. But as the angle of incidence is given their $n λ = 2 d c o s i$ is the formula for finding a peat.