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Question

If a strong diffraction peak is observed when electrons are incident at and angle $$i$$ from the normal to the crystal planes with distances $$d$$ between them (see figure), de-Broglie wavelength $$ {\lambda _{dB}}$$ of electrons can be calculate by the relationship (n is an integer)


A
dsini=nλdB
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B
2dcosi=nλdB
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C
2dsini=nλdB
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D
dcosi=nλdB
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Solution

The correct option is B $$2\,d\,\,\cos \,\,i = n{\lambda _{dB}}$$
$$2dsin\theta ={ n\lambda  }_{ db }$$
$$2dsin\left( 90-i \right) ={ n\lambda  }_{ db }$$
$$2d\left( cosi \right) ={ n\lambda  }_{ db }$$


Physics

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