Question

# If a strong diffraction peak is observed when electrons are incident at and angle $$i$$ from the normal to the crystal planes with distances $$d$$ between them (see figure), de-Broglie wavelength $${\lambda _{dB}}$$ of electrons can be calculate by the relationship (n is an integer)

A
dsini=nλdB
B
2dcosi=nλdB
C
2dsini=nλdB
D
dcosi=nλdB

Solution

## The correct option is B $$2\,d\,\,\cos \,\,i = n{\lambda _{dB}}$$$$2dsin\theta ={ n\lambda }_{ db }$$$$2dsin\left( 90-i \right) ={ n\lambda }_{ db }$$$$2d\left( cosi \right) ={ n\lambda }_{ db }$$Physics

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