Question

If $A^T=\left[\begin{array}{cc}3& 4\\ -1& 2\\ 0& 1\end{array}\right]\text{and}B=\left[\begin{array}{ccc}-1& 2& 1\\ 1& 2& 3\end{array}\right]$,

then find $A^T-B^T$

• A. $\left[\begin{array}{cc}4& 3\\ -3& 0\\ 2& 4\end{array}\right]$
• B. $\left[\begin{array}{cc}1& 0\\ -3& 0\\ -1& -2\end{array}\right]$
• C. $\left[\begin{array}{cc}4& 3\\ -3& 0\\ -1& -2\end{array}\right]$
• D. $\left[\begin{array}{cc}4& 3\\ 3& 0\\ 1& 2\end{array}\right]$

Answer 1

The correct option is C

$\left[\begin{array}{cc}4& 3\\ -3& 0\\ -1& -2\end{array}\right]$

If $A^T=\left[\begin{array}{cc}3& 4\\ -1& 2\\ 0& 1\end{array}\right]\text{and}B=\left[\begin{array}{ccc}-1& 2& 1\\ 1& 2& 3\end{array}\right]$

$B^T=\left[\begin{array}{cc}-1& 1\\ 2& 2\\ 1& 3\end{array}\right]$

$A^T-B^T=\left[\begin{array}{cc}3+1& 4-1\\ -1-2& 2-2\\ 0-1& 1-3\end{array}\right]=\left[\begin{array}{cc}4& 3\\ -3& 0\\ -1& -2\end{array}\right]$