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Question

If a tangent is drawn to the parabola y2=4x through (−2,1), then the point of contact can be:

A
(2,1)
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B
(1,2)
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C
(1,2)
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D
(2,2)
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Solution

The correct option is D (1,2)
The equation of tangent to the parabola y2=4x is xyt+t2
Since, it passes through (2,1)
Therefore, 2t+t2=0
t=1 or t=2
Therefore, one point of contact is (t2,2t)=(1,2)

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