The correct option is D (4,4)
Given parabola : y2=4x
⇒a=1
Equation of chord of contact from (−2,1) is
T=0⇒y(1)−2(x−2)=0⇒y−2x+4=0
Solving this chord of contact and parabola equation will give the point of contact
(2x−4)2=4x
⇒4x2−16x+16=4x
⇒4x2−20x+16=0
⇒x2−5x+4=0
⇒x=1,4
From the equation of chord of contact
for x=1⇒y=−2
for x=4,⇒y=4