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Question

If a tangent is drawn to the parabola y2=4x through the point (2,1) then the points of contact is/are

A
(1,2)
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B
(1,2)
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C
(4,4)
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D
(4,4)
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Solution

The correct option is D (4,4)
Given parabola : y2=4x
a=1
Equation of chord of contact from (2,1) is
T=0y(1)2(x2)=0y2x+4=0

Solving this chord of contact and parabola equation will give the point of contact
(2x4)2=4x
4x216x+16=4x
4x220x+16=0
x25x+4=0
x=1,4
From the equation of chord of contact
for x=1y=2
for x=4,y=4

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