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Question

If A=diag(1  2  3) and B=diag(3  1  4), such that 6A+2B=diag(a  b  c) then the value of (a+b+c) is  


A
20
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B
0 
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C
20 
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D
10 
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Solution

The correct option is C 20 
6A+2B=6 diag(1  2  3)+2 diag(3  1  4)=diag(6  12  18)+diag(6  2  8)=diag(0  10  10)a+b+c=1010=20

Mathematics

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