If a thermometer reads freezing point of water as 20∘C and boiling point as 150∘C, how much thermometer would read when the actual temperature is 60∘C?
A
98∘C
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B
110∘C
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C
40∘C
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D
60∘C
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Solution
The correct option is A98∘C Temperature on any scale can be converted into other scale by x−L.F.PU.F.P−L.F.P= Constant for all scales.
So, x−20150−20=60−0100−0 ⇒x=98∘C