wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a three-hinged parabolic arch, (span l, rise h) is carrying a uniformly distributed load w/unit length over the entire span

A
Shear force will be zero throughout
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Horizontal thrust is (wl2)/8h
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Bending moment will be zero throughout
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
All option are correct
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D All option are correct

1. Support reaction

From FX=0, HA=HB=H

From FY=0, VA+VB=w×l

MA=0

w×l×l2VB×l=0

VB=wl2,VA=wl2

MC=0

w×l2×l4VB×l2+HB×h=0

wl28wl24+HBh=0

HB=wl28h

HA=HB=H=wl28h (Remember)

2. Bending moment at any section xx

BM at xx=VAxHay(w×x)×x2

=wlx2wl28h(4hl2×x×(lx))w×x22

=wlx2w2(xlx2)wx22

=wlx2wlx2+wx22wx22=0

So, BM is zero (0) everywhere

3. Radial shear at x -x

Radial shear at x - x

T=(wl28h)sinθ(wl2wx)cosθ....(A)

y=4hl2(x)(lx)

tanθ=dydθ=4hl2(l2x)

Dividing (A) by cosθ

Tcosθ=(wl28h)tanθ(wl2wx)

w2(l2x)wl2+wx

=wl2wxwl2+wx

Tcosθ=0

So, Radial shear is zero everywhere in the arch.

4. Normal thrust at any section x -x

N=wl28hcosθ+(wl2wx)sinθ

Ncosθ=(wl2wx)tanθ+wl28h

=(wl2wx)4hl2(l2x)+wl28h

N=[(wl2wx)4hl2(l2x)+wl28h]cosθ

Note :
1. If three hinged parabolic arch or a two hinged parabolic arch is subjected to udl throughout its length, BM & radial shear are zero.

2. Cross-section is subjected to only normal thrust every where.

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Analysis of Three Hinged Parabolic Arches
OTHER
Watch in App
Join BYJU'S Learning Program
CrossIcon