If A - B - a - 1- a - 2- a - 3- b - 1- b - 2- b - 3- then n A - n B -A- 4B- 5C- 6D- 7

The correct option is B 5Given that A× B={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3)}. ⇒ A =Set of all first coordinates of A× B= {a, b} and B =Set of all second coord ...

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Cartesian Product

If A × B = a ...

Question

If $A \times B = {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)},$ then $n (A) + n (B) =$ .

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Solution

The correct option is B 5
Given that $A \times B = {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)} .$
$\Rightarrow A = Set of all first coordinates of A \times B$ $= {a, b}$
and $B = Set of all second coordinates of A \times B$
$= {1, 2, 3}$
$\Rightarrow n (A) + n (B) = 2 + 3 = 5$

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If A×B={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3)}, then n(A)+n(B)= .

The correct option is B 5Given that A×B={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3)}. ⇒A=Set of all first coordinates of A×B={a,b} and B=Set of all second coordinates of A×B ={1,2,3} ⇒n(A)+n(B)=2+3=5

If $A \times B = {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)},$ then $n (A) + n (B) =$ .

The correct option is B 5
Given that $A \times B = {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)} .$
$\Rightarrow A = Set of all first coordinates of A \times B$ $= {a, b}$
and $B = Set of all second coordinates of A \times B$
$= {1, 2, 3}$
$\Rightarrow n (A) + n (B) = 2 + 3 = 5$