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Question

If a×b=b×c0 with ac then show that a+c=kb, where k is scalar.

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Solution

a×b=b×c
a×b=c×b
a×b+c×b=0
(a+c)×b=0
So, there are three posibilities:
(i)a+c=0
a=-c which is not the case
(ii)b=0
In this case, a×b=0 too, which is not the case
(iii)a+c= kb ,where k is scalar
which is the only possible scenario.
Hence,a+c= kb ,where k is scalar

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