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Question

If a×cosβ=cosα and b×sinβ=cosα, then value of (a+b)cosβ is

A
cosα(1+cotβ)
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B
sinα1
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C
1cosβ
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D
cosα(1+tanβ)
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Solution

The correct option is A cosα(1+cotβ)
Given,
a×cosβ=cosα and b×sinβ=cosα
a=cosαcosβ and b=cosαsinβ

Therefore, (a+b)cosβ=(cosαcosβ+cosαsinβ)cosβ =cosα+cosαsinβ×cosβ =cosα(1+cosβsinβ) =cosα(1+cotβ)

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