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B
|a→|=|c→|
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C
|c→|=|b→|
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D
none of these
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Solution
The correct option is B|a→|=|c→| Given→a×→b=→c−−−(1)→b×→c=→a−−−(2)calculating(1).→c(→a×→b).→c=→c.→c[→a→b→c]=|→c|2Andalso(2).→a→a(→b×→c)=→a.→a=|a|2Hence,|a|2=|→c|2⇒|→a|=|→c|OptionBisthecorrectanswer.