If a total distance of 750 m is covered in a time interval of 25 s,the average speed is
3, 974 mph
30 m/s
30 mph
3 mph
Average speed = (Total Distance) / Total time
= 750 m / 25 s
=30 m/s
Explain clearly, with examples, the distinction between: a) magnitude of displacement (sometimes called distance) over an interval of time, and the total length of path covered by a particle over the same interval; b) magnitude of average velocity over an interval of time, and the average speed over the same interval. [Average speed of a particle over an interval of time is defined as the total path length divided by the time interval]. Show in both (a) and (b) that the second quantity is either greater than or equal to the first. When is the equality sign true? [For simplicity, consider one-dimensional motion only].