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Question

If a trader sells two cars each at Rs. 404415 and gains 15% on the first and loses 15% on the second, then find his profit or loss percent on the whole transaction?

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Solution

S.P of both cars = Rs 404415
For the first car gains 15%
Thus, C.P = SP(100+gain×100=404415100+15×100
=404415115×100=Rs3,51,665
For the second car, he loses 15%
Thus, C.P = SP(100los×100=404415(10015)×100
=40441585×100=Rs4,75,782
Total C.P = 351665+475782=Rs 8,27,447
Total S.P = Rs 4,04,415 × 2 = Rs 8,08,830
Total loss = 8,27,447 - 8,08,830 = Rs . 18,617
loss % = Rs18,6178,27,447×100 = 2.25%

1244995_1532773_ans_1f70442ed4714dcdb15dd519720e87ec.PNG

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