Question

If a train 110 m long passes a telegraph pole in 3 seconds, then the time taken by it to cross a railway platform 165 m long is

• A. 3 sec
• B. 4 sec
• C. 5 sec
• D. 7.5 sec

Answer 1

The correct option is D 7.5 sec

$Speed=\left(\frac{110}{3}\right)m/sec\text{Time taken to cross railway platform}=\left[\right(110+165)\times \frac{3}{110}]sec=(275\times \frac{3}{110})sec=7.5sec$