Question

If a triangle has angles ${45}^{\circ },{45}^{\circ }$, and ${90}^{\circ }$, what is the value of BC when AC = $28\sqrt{2}$ m .

Answer 1

We have theorem :

" If the angles of a triangle are ${45}^{\circ },{45}^{\circ }$, and ${90}^{\circ }$,then each of the perpendicular sides is $\frac{1}{\sqrt{2}}$ times the hypotenuse " .

AC= hypotenuse = $28\sqrt{2}$ m .


So, BC = $\frac{1}{\sqrt{2}}\times 28\sqrt{2}=28m$