If a triangle in which AB = 4 cm, ∠CAB = $45^{0}$ and BC = 2.92 cm is constructed then the side length of AC is:

2.54 cm

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3.54 cm

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4.54 cm

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4.1 cm

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Solution

The correct option is B
3.54 cm

After constructing the triangle as shown above. Measure the side length AC. The side length AC is 3.54 cm.

Step 1: Draw a line, AB, 4 cm long.
Step 2: Draw an arc at 45 degrees with A as the center
Step 3: Draw an arc of radius 2.92 cm with B as the center.
Step 4: Mark, C, the point of intersection of the two arcs and measure AC

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Similar questions

Q. Construct a triangle in which AB = 4 cm, ∠CAB =

45^{0}

and BC = 2.92 cm. The side length of AC is:

Q. Triangle ABC is constructed with AB = 4 cm, ∠CAB =

45^{0}

and BC = 2.92 cm. Two perpendicular bisectors are drawn of side AB and BC intersecting at point O. The length of OA is:

Q. Construct a triangle in which AB = 4 cm, ∠CAB =

45^{0}

and BC = 2.92 cm. Draw a circle circumscribing the triangle ABC. The radius of the circle is:

Triangle ABC is constructed with AB = 4 cm, ∠CAB = $45^{0}$ and BC = 2.92 cm. Draw two perpendicular bisectors of side AB and BC. These two bisectors will intersect at a point. State whether True or False.

Construct a

△ A B C

in which:

A B = 5.4 c m

∠ C A B = 45^{0}

and

A C + B C = 9 c m

Then the length of

A C

(in

c m .

) is:

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If a triangle in which AB = 4 cm, ∠CAB = 450 and BC = 2.92 cm is constructed then the side length of AC is:

If a triangle in which AB = 4 cm, ∠CAB = $45^{0}$ and BC = 2.92 cm is constructed then the side length of AC is: