If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is

(a) $\frac{3}{10}$

(b) $\frac{29}{100}$

(c) $\frac{1}{3}$

(d) $\frac{7}{25}$

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Solution

GIVEN: A two digit number is chosen at random

TO FIND: Probability that the number chosen is a multiple of 3

Total two digit numbers is 90

Two digit Numbers multiple of 3 are 12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99

Hence total two digit numbers multiple of 3 are 30

We know that PROBABILITY =

Hence probability that the number chosen is a multiple of 3 is equal to

Hence the correct option is

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If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is (a) 310 (b) 29100 (c) 13 (d) 725

If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is

(a) $\frac{3}{10}$

(b) $\frac{29}{100}$

(c) $\frac{1}{3}$

(d) $\frac{7}{25}$