If a uniform beam of $1 m$ is balanced as shown above, what would be the moment of force F about point W?

110 N c m

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40 N c m

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220 N c m

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80 N c m

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Solution

The correct option is C $220 N c m$
If the uniform beam is in rotational equilibrium, net torque on the beam about point U must be zero i.e. $τ_{U} = 0$
Consider anti-clockwise direction to be positive.
$∴$ $τ_{U} = - (F) (40) + (3) (10) + (2) (40) = 0$
$⟹ F = 2.75 N$
Torque of $F$ about W, $τ = F \times 80 = 2.75 \times 80 = 220 N c m$

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