If a unit charge is taken from one point to another over an equipotential surface, then
A
work is done on the charge
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B
work is done by the charge
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C
work on the charge is constant
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D
no work is done
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Solution
The correct option is D no work is done → We know equipotential surface has constant potential and they are perpendicular to electric field. We know work done =ΔV×Q As there is no change in V while moving on equipotential surface Work done =0