If a variable takes the discrete values -4- -7-2- -5-2- -3- -2-1-2- -1-2- -5-0then the median is

The correct option is A α 54Arrange the data in increasing order: nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; α ...

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Median

If a variable...

Question

If a variable takes the discrete values $α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2 α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),$
then the median is

α - \frac{5}{4}

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α - \frac{1}{2}

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α - 2

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α + \frac{5}{4}

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Solution

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Similar questions

α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2 α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0)

α + 4

α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

(\frac{1}{{sec}^{2} α - {cos}^{2} α} + \frac{1}{csc^{2} α - {sin}^{2} α}) \times {sin}^{2} α {cos}^{2} α = \frac{1 - {sin}^{2} α {cos}^{2} α}{2 + {sin}^{2} α {cos}^{2} α}

α

∣ ∣ ∣ ∣ ∣ \begin{matrix} (1 + α)^{2} & (1 + 2 α)^{2} & (1 + 3 α)^{2} (2 + α)^{2} & (2 + 2 α)^{2} & (2 + 3 α)^{2} (3 + α)^{2} & (3 + 2 α)^{2} & (3 + 3 α)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = - 648 α

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