If a variable takes the discrete values -4- -7-2- -5-2- -3- -2- -1-2- -1-2- -5-0- then the median is -

The correct options are A D Arrange the data as α 7/2, α 3, α 5/2, α 2, α 1/2, α + 1/2, α+4, α + 5 Median=a 2+ α 1/2/2=2 α 5/2/2=α 5/4 ...

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Byju's Answer

Standard X

Mathematics

Finding Median term

If a variable...

Question

$I f a v a r i a b l e t a k e s t h e d i s c r e t e v a l u e s α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0), t h e n t h e m e d i a n i s :$

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Solution

The correct options are
A
D
$A r r a n g e t h e d a t a a s α - \frac{7}{2}, α - 3, α - \frac{5}{2}, α - 2, α - \frac{1}{2}, α + \frac{1}{2}, α + 4, α + 5 M e d i a n = \frac{a - 2 + α - \frac{1}{2}}{2} = \frac{2 α - \frac{5}{2}}{2} = α - \frac{5}{4}$

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Similar questions

Q. If a variable takes the discrete values

α + 4

α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

then the median of these values is

Q. If a variable takes the discrete values

α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2 α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

then the median is

Q. If

α

is non-real and

α = \sqrt[5]{1},

then the value of

2^{∣ ∣ 1 + α + α^{2} + α^{3} - α^{- 1} - α^{- 2} ∣ ∣}

is equal to

Two lines $L_{1} : x = 5, \frac{y}{3 - α} = \frac{z}{- 2}$ and $L_{2} : x = α, \frac{y}{- 1} = \frac{z}{2 - α}$ are coplanar. Then, $α$ can take value(s)

Q. If

{[1 - sin (π + α) + cos (π + α)]}^{2} + {[1 - sin (\frac{3 π}{2} + α) + cos (\frac{3 π}{2} - α)]}^{2} = a + b sin 2 α

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a

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If a variable takes the discrete values α+4, α−72, α−52, α−3, α−2, α+12, α−12, α+5(α>0), then the median is:

The correct options are A D Arrange the data asα−72, α−3, α−52, α−2, α−12, α+12, α+4, α+5Median=a−2+α−122=2α−522=α−54

$I f a v a r i a b l e t a k e s t h e d i s c r e t e v a l u e s α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0), t h e n t h e m e d i a n i s :$

The correct options are
A
D
$A r r a n g e t h e d a t a a s α - \frac{7}{2}, α - 3, α - \frac{5}{2}, α - 2, α - \frac{1}{2}, α + \frac{1}{2}, α + 4, α + 5 M e d i a n = \frac{a - 2 + α - \frac{1}{2}}{2} = \frac{2 α - \frac{5}{2}}{2} = α - \frac{5}{4}$