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Median

If a variable...

Question

If a variable takes the discrete values $α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0)$ ,then the median is

A

α - \frac{5}{4}

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B

α - \frac{1}{2}

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C

α - 2

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D

α + \frac{5}{4}

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Solution

The correct option is A $α - \frac{5}{4}$
Arrange the data as: $α - \frac{7}{2}, α - 3, α - \frac{5}{2}, α - 2, α - \frac{1}{2}, α + \frac{1}{2}, α + 4, α + 5,$

Median $= \frac{a - 2 + α - \frac{1}{2}}{2} = \frac{2 α - \frac{5}{2}}{2} = α - \frac{5}{4}$

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Q. If a variable takes the discrete values

α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2 α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

then the median is

Q. If a variable takes the discrete values

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α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2, α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

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α + 4, α - \frac{7}{2}, α - \frac{5}{2}, α - 3, α - 2 α + \frac{1}{2}, α - \frac{1}{2}, α + 5 (α > 0),

then the median is

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α = \sqrt[5]{1},

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