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Byju's Answer
Standard X
Mathematics
Step-Deviation Method of Finding Mean
If a variable...
Question
If a variable takes values 1,2,3,....n with frequencies
1
2
,
2
2
,
.
.
.
n
2
.
.
.
.
Then the mean is
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Solution
M
e
a
n
=
∑
f
i
x
i
∑
f
i
=
1
×
1
2
+
2
×
2
2
+
3
×
3
2
+
−
−
−
−
−
−
−
n
×
n
2
1
2
+
2
2
+
3
2
+
−
−
−
−
−
−
−
−
−
n
2
=
∑
n
3
∑
n
2
=
n
2
(
n
+
1
)
2
×
6
4
n
(
n
+
1
)
(
2
n
+
1
)
=
3
n
(
n
+
1
)
2
(
2
n
+
1
)
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Similar questions
Q.
If a variable takes values
0
,
1
,
2
,
3
,
.
.
.
,
n
with frequencies
1
,
C
(
n
,
1
)
,
C
(
n
,
2
)
,
C
(
n
,
3
)
,
.
.
.
,
C
(
n
,
n
)
respectively, then the arithmetic mean is
Q.
If a variable
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takes values
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,
1
,
2
,
.
.
.
.
n
with frequencies proportional to the binomial coefficients
n
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0
,
n
C
1
,
n
C
2
,
.
.
.
.
.
.
n
C
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, then mean of distribution is
Q.
A variable takes the values of
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,
1
,
2
,
.
.
.
.
.
.
n
with frequencies proportional to the binomial coefficients
n
C
0
,
n
C
1
,
.
.
.
.
.
.
,
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n
+
, then mean of the distribution is
Q.
If a variable takes the values
0
,
1
,
2
,
.
.
.
,
n
with corresponding frequencies as binomial coefficients
n
C
0
,
n
C
1
,
.
.
.
,
n
C
n
, then the mean of distribution is
Q.
If a variable takes values
0
,
1
,
2
,
3
,
.
.
.
.
,
n
with frequencies
q
n
,
n
C
1
q
n
−
1
p
,
n
C
2
q
n
−
2
p
2
,
.
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,
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