The correct option is C −12≤x≤−4
Given, −2x+3≥11
Subtract both sides of the inequality by 3
−2x+3−3≥11−3
⇒−2x≥8
Divide both sides of the inequality by -2 and reverse the inequality.
−2x−2≤8−2
⇒x≤−4…(i)
⇒x is less than or equal to −4
Also, −x−5≤7
Add both sides of the inequality by 5
−x−5+5≤7+5
⇒−x≤12
Multiply both sides of the inequality by -1 and reverse the inequality.
−x×−1≥12×−1
⇒x≥−12…(ii)
⇒x is greater than or equal to −12
Combining (i) and (ii), we get
−12≤x≤−4
⇒x is greater than or equal to −12 and less than or equal to −4