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Question

If a vector AB=2^i^j+^k and OB=3^i4^j+4^k, then the position vector OA is

A
3^i2^j+^k
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B
3^i^j+^k
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C
^i+3^j2^k
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D
^i3^j+3^k
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Solution

The correct option is D ^i3^j+3^k
AB=OBOA
OA=OBAB
OA=(3^i4^j+4^k)(2^i^j+^k)
OA=^i3^j+3^k

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