Question

If a vertex of triangle is $(3,3)$ and the mid points of two sides through this vertex are $(2,\frac{3}{2})$ and $(4,\frac{3}{2})$ then the centroid of the triangle is given by:

• A. $(1,3)$
• B. $(3,0)$
• C. $(3,1)$
• D. $(0,3)$

Answer 1

Answer: (C)

$(3,1)$

$(\frac{x_1+3}{2},\frac{y_1+3}{2})=(2,\frac{3}{2})|(\frac{x_2+3}{2},\frac{y_2+3}{2})=(4,\frac{3}{2})$
$x_1=1,y_1=0|x_2=5y_2=0$
$B\equiv (1,0)|$
$C\equiv (5,0)$
$\therefore G=(3,1)$