If a volume of a mixture of ${C O}_{2}$ and $C O$ increases by $20$ % on passing over hot coke, the percentage of ${C O}_{2}$ in the original mixture is:
$(C + {C O}_{2} ⟶ 2 C O)$

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Solution

The correct option is C $20$ %
Consider a mixture of $C O_{2}$ and $C O$ in which
$C O_{2} - x$ & $C O = 100 - x$ i.e., total is $100$ volume.
According to the question after passing mixture are hot coke an increase by $20 %$ is seem i.e.,
By the reaction given we know $C O_{2}$ change to $C O$ with a doubling of volume
$\Rightarrow 2 x + (100 - x) = 120$
$\Rightarrow x = 20$

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