If a water falls from a dam into a turbine wheel $19.6 m$ below, then the velocity of water at the turbines is ( take $g = 9.8 m / s^{2}$ )

9.8 m / s

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19.6 m / s

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39.2 m / s

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98.0 m / s

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Solution

The correct option is B $19.6 m / s$
Initial speed of water $u = 0$
Acceleration due to gravity $g = 9.8 m / s^{2}$
Distance $S = 19.6 m$
Using $v^{2} - u^{2} = 2 g S$
$∴$ $v^{2} - 0 = 2 \times 9.8 \times 19.6$
$⟹ v = \sqrt{(19.6)^{2}} = 19.6 m / s$

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If a water falls from a dam into a turbine wheel 19.6m below, then the velocity of water at the turbines is ( take g=9.8m/s2)

The correct option is B 19.6m/sInitial speed of water u=0Acceleration due to gravity g=9.8 m/s2Distance S=19.6 mUsing v2−u2=2gS∴ v2−0=2×9.8×19.6⟹ v=√(19.6)2=19.6 m/s

If a water falls from a dam into a turbine wheel $19.6 m$ below, then the velocity of water at the turbines is ( take $g = 9.8 m / s^{2}$ )

The correct option is B $19.6 m / s$
Initial speed of water $u = 0$
Acceleration due to gravity $g = 9.8 m / s^{2}$
Distance $S = 19.6 m$
Using $v^{2} - u^{2} = 2 g S$
$∴$ $v^{2} - 0 = 2 \times 9.8 \times 19.6$
$⟹ v = \sqrt{(19.6)^{2}} = 19.6 m / s$