If a wire is bent into the shape of s square, the area of the square is $49 c m^{2}$ . When the wire is bent into a semi-circle shape, find the radius of the semi-circle. (Take $π = \frac{22}{7})$ .

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Solution

Area of eqution $= a^{2} = 4 a$ cm $a = 7$ cm

length of wire $= 4 a = 28$ cm

so perimeter of semi circle shape $= π r$

So $\frac{22}{7} \times r = 28 r = \frac{28 \times 7}{22} = 8.91$ cm

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If a wire is bent into the shape of s square, the area of the square is 49 cm2. When the wire is bent into a semi-circle shape, find the radius of the semi-circle. (Take π=227).

Area of eqution =a2=4a cm a=7 cm length of wire =4a=28 cmso perimeter of semi circle shape =πrSo 227×r=28r=28×722=8.91 cm

If a wire is bent into the shape of s square, the area of the square is $49 c m^{2}$ . When the wire is bent into a semi-circle shape, find the radius of the semi-circle. (Take $π = \frac{22}{7})$ .

Area of eqution $= a^{2} = 4 a$ cm $a = 7$ cm

length of wire $= 4 a = 28$ cm

so perimeter of semi circle shape $= π r$

So $\frac{22}{7} \times r = 28 r = \frac{28 \times 7}{22} = 8.91$ cm