Question

If A(x,0), B(-4,6), and C(14, -2) form an isosceles triangle with AB=AC, then x=

• A. 37/9
• B. 31/9
• C. -3
• D. -4

Answer 1

The correct option is A 37/9

AB = AC or $A{B}^2=A{C}^2$
or ${(x+4)}^2+{(0-6)}^2={(x-14)}^2+{(0+2)}^2$
or $x^2+8x+16+36=x^2-28x+196+4$
or 36x = 148 or x = $\frac{148}{36}=\frac{37}{9}$