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Question

If A=−x2−5x+3 and B=4x2+7x−1, then calculate 32B−2A?

A
4x2+312x92
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B
4x2+412x152
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C
8x2+312x92
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D
8x2+412x152
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Solution

The correct option is C 8x2+412x152
A=x25x+3 and 32B=32(4x2+7x1)
Then 32B2A=32((4x2+7x1))2(x25x+3)
= 6x2+212x32+2x2+10x6
= 6x2+2x2+212x+5x326
= 8x2+412x152

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