If ax2+bx+c=0,a,b,c ϵ R , has no real root, then
f(x)=ax2+bx+c=0 has no real root ⇒ f(x) has same sign for all x ϵ R
⇒ f(0)f(1)> 0 ⇒ c(a+b+c)> 0