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Question

If ax2+bx+c=0,a0,a,b,cR has distinct real roots in (1,2) then a and 5a+2b+c have

A
same sign
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B
opposite sign
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C
not detremined
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D
none of these
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Solution

The correct option is B same sign
Let x1 and x2 be two roots of ax2+bx+c=0
1<x1<2 and 1<x2<2
Now a(5a+2b+c)=a2(5+2ba+ca)
=a2(5+2(1)(x1+x2)+x1x2)=a2((x12)(x22)+1)>0
Hence a and 5a+2b+c are of same sign.

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