If |A X B|=(3)^1/2 A.B, then the value of |A+B| is
First of all the question should be
|a×b|=√3a.b because a vector can never be equal to a scalar.
So |a×b|=ab sintheta where theta is angle between 2 vectors.
a.b=ab costheta
Equating above two we get
Sintheta=√3costheta
=> tantheta =√3
=> theta =60 ° or 240° or more general theta = nπ+60°.
so |a+b| =√|a|^2+|b|^2+2|a||b| costheta)
Since we have two different values of theta there are two different answers.
1st answer is√|a|^2+|b|^2+|a||b| )
2nd answer is√|a|^2+|b|^2-|a||b| )