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Question

If ax=b;by=c;cz=a & 2x2+5y2+z26xy+2yz2xz=0 then value of x3+3y3+5z3 is

A
0
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B
1
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C
8
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D
12
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Solution

The correct option is D 8
axyz=axyz=1 ...(i)
(y+zx)2+(x2y)2=0
so , y+zx=0 & x=2y
so , x=2y & z=y
so , 2y3=z3=12 & z=y
x3+3y3+5z3=8

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