CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
116
You visited us 116 times! Enjoying our articles? Unlock Full Access!
Question

If ax=b;by=c;cz=a & 2x2+5y2+z26xy+2yz2xz=0 then value of x3+3y3+5z3 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 8
axyz=axyz=1 ...(i)
(y+zx)2+(x2y)2=0
so , y+zx=0 & x=2y
so , x=2y & z=y
so , 2y3=z3=12 & z=y
x3+3y3+5z3=8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Division of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon