If ax - by - cz - abc- then 1x - 1y - 1z - -

The correct option is D 1 a^x=b^y=c^z=abc ∴ x= ln(abc)ln a ∴ y= ln(abc)ln b ∴ z= ln(abc)ln c 1x + 1y + 1z = ln a + ln b + ln cln ...

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Conduction Law

If ax = by ...

Question

If $a^{x} = b^{y} = c^{z} =$ abc, then $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = . . . . . . .$

- 1

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x y z

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1

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\frac{1}{x y z}

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Similar questions

If $a^{x - 1} = b c, b^{y - 1} = a c, c^{z - 1} = a b$ such that $x, y, z$ are integers then value of $x y + y z + z x - x y z$ is

a^{x} = b^{y} = c^{z} = a b c

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} =

a^{x} = b^{y} = c^{z}

a b c = 1

\frac{1}{x} + \frac{1}{y} + \frac{1}{z}

a^{x - 1} = b c, b^{y - 1} = a c, c^{z - 1} = a b

x y + y z + z x - x y z = 0

a^{x} = b, b^{y} = c, c^{z} = a

x y z = 1

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