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Question

If A={x:x23x+2=0} and R is a universal relation on A, then R is

A
{(1,1),(2,2)}
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B
{(1,1)}
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C
{ϕ}
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D
{(1,1),(1,2),(2,1),(2,2)}
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Solution

The correct option is D {(1,1),(1,2),(2,1),(2,2)}
x23x+2=0(x1)(x2)=0x=1,2A={1,2}A×A={(1,1),(1,2),(2,1),(2,2)}

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