Question

If $A=\{x:x^2-5x+6=0\},B=\{2,4\},C=\{4,5\}$, then $A\times (B\cap C)$ is

• A. $\left\{\right(2,4),(3,4\left)\right\}$
• B. $\left\{\right(4,2),(4,3\left)\right\}$
• C. $\left\{\right(2,4),(3,4),(4,4\left)\right\}$
• D. $\left\{\right(1,2\left)\right\}$

Answer 1

The correct option is A $\left\{\right(2,4),(3,4\left)\right\}$

$A=\{2,3\},B=\{2,4\},C=\{4,5\}\Rightarrow B\cap C=4\therefore A\times (B\cap C)=\left\{\right(2,4),(3,4\left)\right\}$